explain how PT (NH3)4 cl2 and PT (NH 3)6 cl4 differ in their electrolytic conductance give the hybridisation of pt in these compounds
Answers
There is a slight error in the question. It is Pt Cl2 (NH3)2 and not Pt (NH3)4 cl2.
The answer is given as follows -
[Pt (NH3)6] Cl4 is also known as hexaammine platinum (IV) chloride. It consists of 4 Cl- ions (free ions) and 1 cation. Thus, the total number of of ions is5.
[Pt Cl2 (NH3)2] or diammine dichloro platinum (II), consists of zero number of free ions.
As we know, the electrical conductivity increases with the increase of number of ions. Therefore, [Pt (NH3)6] Cl4 exhibits more electrical conductance than [Pt Cl2 (NH3)2].
Answer:
Hybrid state of Pt in [Pt(NH3)2Cl2] is dsp2 and it has square planar geometry while in [Pt(NH3)6]Cl4 the hybrid state of Pt is d2sp3 and it has octahedral geometry.
Pt in [Pt(NH3)2Cl2] = dsp2 (square planar)
Pt in [Pt(NH3)6]Cl4 =d2sp3 (octahedral)