Explain how you will determine experimentally the position of centre of gravity for a triangular lamina?
Answers
Answered by
10
Answer:
The process of finding centre of gravity of a triangular lamina is a very simple one. It can be experimentally described as below:
- Make holes near all the 3 edges of the lamina at a very short and equal distance from the lamina.
- Fix a nail in the wall at or near the eye level such that is becomes possible to hang this lamina from all 3 of it's edges.
- Take the lamina and hang it on the nail fixed on the wall. The centre of gravity will lie just below the nail but exact location at this point of time will be unknown.
- Draw a straight line below the nail onto the lamina.
- Hang the Lamina from the second edge.
- Draw another straight line and this line will intersect the previously drawn line at one point.
- Repeat the process by hanging the lamina from it's 3rd edge as well.
- All the 3 straight line thus drawn will intersect at one common point.
- This point is the centre of gravity of the Triangular Lamina.
Answered by
10
Centre of Gravity of Trainguar Lamina :
- Take a thick cardboard sheet and cut in the form of a traingle
- Let A, B, C be the corrners of the traingular lamina
- note the midpoints of side AB, BC and AC.
- Let them be D, E, and F respectively
- Join CD, AE and BF.
- These Lines meet at a point G.
- This point G is called as geometric mid point of Lamina which is called as Centroid.
- Suspend the lamina at the point G . It remains Horizontal.
- Therefore G is the centre of gravity of triangular Lamina.
Attachments:
Similar questions
India Languages,
7 months ago
Hindi,
7 months ago
Math,
1 year ago
Social Sciences,
1 year ago
English,
1 year ago