Question

explain hybridsation in PBr5(in solid state)​

Answer 1

Answer:

PBr5 exists only in gaseous state it's hybridization is sp3d.

Explanation:

COH_2: Carbon, being the central atom, has 3 groups around it, so it is sp^2 hybridized because it needs 3 orbitals, 1 s and 2 p.

Answer 2

Answer: The hybridization of $PBr_5$ is $sp^3d$

Explanation:

The equation used to calculate hybridization follows:

$\text{Number of electron pair}=\frac{1}{2}[V+N-C+A]$

where,

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

For the given compound, $PBr_5$

We know that:

$V=5\\N=5\\C=0\\A=0$

Putting values in above equation, we get:

$\text{Number of electron pair}=\frac{[5+5]}{2}=5$

The number of electron pair are coming out to be 5. This means that the hybridization will be $sp^3d$ and the electronic geometry of the molecule will be trigonal bipyramidal.

Hence, the hybridization of $PBr_5$ is $sp^3d$