Question

explain it properly
A mass of 100g strikes a wall with a speed 5m/s at an angle of 60°, and rebounds with the same speed. If the contact time is 2*10^ - 3, what is the force applied by the wall?
A. 250✓3N to right
B. 250 N to right
C. 250✓3N to left
D. 250 N to left

Answer 1

I hope it will help you

Answer 2

Answer:

Force, F = 433.01 N (due left)

Explanation:

It is given that,

Mass of the object, m = 100 g = 0.1 kg

Speed of the object, v = 5 m/s

It is thrown at an angle of 60 degrees.

The time of contact, $t=2\times 10^{-3}\ s$

As the object rebounds with the same speed. The change in velocity is given by :

$\Delta v=2v\ sin\theta$

Let F is the force applied by the wall. Using second law of motion as :

$F=ma$

$F=m\dfrac{\Delta v}{\Delta t}$

$F=m\ kg\dfrac{2v\ sin\theta}{\Delta t}$

$F=0.1\ kg\dfrac{2\times 5\ sin(60)}{2\times 10^{-3}}$

F = 433.01 N (due left)

So, the force applied by the wall is 433.01 N. Hence, this is the required solution.