Math, asked by AkshithaZayn, 1 year ago

Explain :

<> Trigometric Basics.

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Answers

Answered by Apxex
7
Hey dear here is your answer in the attachment
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AkshithaZayn: thanks for answering
Apxex: np
Answered by THEmultipleTHANKER
72

\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\sf Trigonometry\: Table \\ \begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\boxed{\red{\begin{array}{ |c |c|c|c|c|c|} \bf\angle A &amp; \bf{0}^{ \circ} &amp; \bf{30}^{ \circ} &amp; \bf{45}^{ \circ} &amp; \bf{60}^{ \circ} &amp; \bf{90}^{ \circ} \\ \\ \rm sin A &amp; 0 &amp; \dfrac{1}{2}&amp; \dfrac{1}{ \sqrt{2} } &amp; \dfrac{ \sqrt{3}}{2} &amp;1 \\ \\ \rm cos \: A &amp; 1 &amp; \dfrac{ \sqrt{3} }{2}&amp; \dfrac{1}{ \sqrt{2} } &amp; \dfrac{1}{2} &amp;0 \\ \\ \rm tan A &amp; 0 &amp; \dfrac{1}{ \sqrt{3} }&amp;1 &amp; \sqrt{3} &amp; \rm \infty \\ \\ \rm cosec A &amp; \rm \infty &amp; 2&amp; \sqrt{2} &amp; \dfrac{2}{ \sqrt{3} } &amp;1 \\ \\ \rm sec A &amp; 1 &amp; \dfrac{2}{ \sqrt{3} }&amp; \sqrt{2} &amp; 2 &amp; \rm \infty \\ \\ \rm cot A &amp; \rm \infty &amp; \sqrt{3} &amp; 1 &amp; \dfrac{1}{ \sqrt{3} } &amp; 0 \end{array}}}}\end{gathered}\end{gathered}\end{gathered} \end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}

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More Trigonometry Formulae-

1. tan θ = sinθ/cosθ

2. cossecθ = 1/ sinθ

3. sec θ = 1/cosθ

4. Cotθ = 1/ tanθ

5. Sin²θ+ Cos²θ= 1

6. Sec²θ - tan²θ = 1

7. cosec ²θ - cot²θ = 1

8. sin(90°−θ) = cos θ

9. cos(90°−θ) = sin θ

10. tan(90°−θ) = cot θ

11. cot(90°−θ) = tan θ

12. sec(90°−θ) = cosec θ

13. cosec(90°−θ) = sec θ

14. Sin2θ = 2 sinθ cosθ

15. cos2θ = Cos²θ- Sin²θ

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