Question

Explain me by solving.​

Answer 1

$\large{\underline{\underline{\mathfrak{\green{\sf{Given \:Equation:-}}}}}}$.

$\red{\:X^2-7X+10\:=\:0}$.

$\large{\underline{\underline{\mathfrak{\pink{\sf{Find\:Here:-}}}}}}$.

★$\yellow{\:Value\:of\:X}$.

$\large{\underline{\underline{\mathfrak{\red{\sf{Explanation:-}}}}}}$.

$\implies\:x^2-7x+10\:=\:0$.

$\implies\:x^2-5x-2x+10\:=\:0$.

$\implies\:x(x-5)-2(x-5)\:=\:0$.

$\implies\:(x-2)((x-5)\:=\:0$.

$\implies\:(x-2)\:=\:0\:\:,\:Or\:(x-5)\:=\:0$.

$\implies\:x\:=\:0\:\:,\:Or\:x\:=\:5$.

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Answer 2

$\huge{\underline{\mathbb{\red{Answer}}}}$

$=> {x}^{2} - 7x + 10 = 0$

$= > {x}^{2} - 5x - 2x + 10 = 0$

$= > x(x - 5) - 2(x - 5) = 0$

$= > (x - 2)(x - 5) = 0$

$= > (x - 2) = 0 \: or \: (x - 5) = 0$

$== > x = 0 \: or \: x = 5$

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$\huge{\underline{\underline{\mathfrak{Thank you}}}}$