explain me how to calculate mass of water present in 499 gm of cus04.5h20
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The gram molecular mass of CuSO₄.5H₂O is 249.5 grams(1mole)
In it there are 5 molecules of water weighing 90 grams.
Now,
499 grams of CuSO₄.5H₂O indicates 2 moles of it.
so the mass of water present = 90 x 2 = 180 grams
In it there are 5 molecules of water weighing 90 grams.
Now,
499 grams of CuSO₄.5H₂O indicates 2 moles of it.
so the mass of water present = 90 x 2 = 180 grams
fbm:
thanks
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