Explain MOED of O2 ?
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We know that Oxygen has atomic number = 8. Thus, the electronic configuration for an atom of oxygen in the ground state can be given as – $1{s^2}2{s^2}2{p^4}$ One atom of oxygen has 8 electrons. Thus, two atoms will possess 16 electrons i.e. Oxygen molecules will have 16 electrons.
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