explain pgt theorem with fig.
i will mark it as brainlist
sonurathod888:
ao sun
good morning both
mai vo boy se bat kerti the aur yaha nshe kerti the tho kya gussa ho
mere se
nahi mai tum se gussa kyu houge friends se kabhi koi gussa hota h kya
happy Raksha Bandhan bhai
thnx
and same 2 u
bhena
hi
Answers
Answered by
4
hey here is your ans
Attachments:
h wo to pata h ki aditya ek boy ka naam h
brainly pr h kya
usne pahale muze friend bana ya
aur pher kuch deno bad bola ke i hate u
tho mai ne bhe bol deya thek h
ja udher
mai ne bhe bola i also hate u
gussa aaya kya re renuka
nahi yrr
happy raksha bandhan meri bheno
Answered by
2
The Pythagorean Theorem says that, in a right triangle, the square of a (a2) plus the square of b (b2) is equal to the square of c (c2):
a2 + b2 = c2
Proof of the Pythagorean Theorem using Algebra
We can show that a2 + b2 = c2 using Algebra
Take a look at this diagram ... it has that "abc" triangle in it (four of them actually):

Area of Whole Square
It is a big square, with each side having a length of a+b, so the total area is:
A = (a+b)(a+b)
Area of The Pieces
Now let's add up the areas of all the smaller pieces:
First, the smaller (tilted) square has an area of:c2
Each of the four triangles has an area of:ab2
So all four of them together is:4ab2 = 2ab
Adding up the tilted square and the 4 triangles gives:A = c2 + 2ab
Both Areas Must Be Equal
The area of the large square is equal to the area of the tilted square and the 4 triangles. This can be written as:
(a+b)(a+b) = c2 + 2ab
NOW, let us rearrange this to see if we can get the pythagoras theorem:
Start with:(a+b)(a+b) = c2 + 2ab
Expand (a+b)(a+b):a2 + 2ab + b2 = c2 + 2ab
Subtract "2ab" from both sides:a2 + b2 = c2
I Hope this is helpful for u......
a2 + b2 = c2
Proof of the Pythagorean Theorem using Algebra
We can show that a2 + b2 = c2 using Algebra
Take a look at this diagram ... it has that "abc" triangle in it (four of them actually):

Area of Whole Square
It is a big square, with each side having a length of a+b, so the total area is:
A = (a+b)(a+b)
Area of The Pieces
Now let's add up the areas of all the smaller pieces:
First, the smaller (tilted) square has an area of:c2
Each of the four triangles has an area of:ab2
So all four of them together is:4ab2 = 2ab
Adding up the tilted square and the 4 triangles gives:A = c2 + 2ab
Both Areas Must Be Equal
The area of the large square is equal to the area of the tilted square and the 4 triangles. This can be written as:
(a+b)(a+b) = c2 + 2ab
NOW, let us rearrange this to see if we can get the pythagoras theorem:
Start with:(a+b)(a+b) = c2 + 2ab
Expand (a+b)(a+b):a2 + 2ab + b2 = c2 + 2ab
Subtract "2ab" from both sides:a2 + b2 = c2
I Hope this is helpful for u......
tho usne muze i like u vagera vagera bola
a ur vo boy paki. hai
haa bolo
vo paki. hai
kha h issse app mai
aur jub mai ne kaha disturb mat karna tho
vo bad words use karne laga
aur tuze paki. mai leke aajauga
omg isse app ka boy h kya vooo...
shaddi karni hai muze tere sat
Similar questions