Question

if alpha is one root of the equation 4X2 + 2X - 1 =0, then its other root is given by

Answer 1

HEYA!
---------

-----------------------------------------------------------------------------------------------------
✴ROOTS OF A QUADRATIC POLYNOMIAL✴
-----------------------------------------------------------------------------------------------------

Given Equation ,

$4x {}^{2} + 2x - 1 \\ \\ using \: the \: quadratic \: formula \: \\ \\ x = \frac{ - b \frac{ + }{ - } \sqrt{b {}^{2} - 4ac } }{2a} \\ \\ here \: a = 4 \: \: b = 2 \: \: and \: \: c = - 1 \: \: \: calculating \: discriminant \: \sqrt{d } \\ \\ d = \sqrt{b {}^{2} - 4ac} \\ \\ = > \sqrt{4 - 4 \times - 4} \\ \\ = \sqrt{4 + 16} = \sqrt{20} \\ \\ putting \: in \: quad. \: \: formula \: \: \\ \\ x = \frac{ - 2 + \sqrt{20} }{8} \\ \\ x = \frac{ - 2 - \sqrt{20} }{8}$

These are the required roots of the polynomial.


$if \: one \: root \: is \: taken \: as \: \alpha \: \: then \: the \: other \: root \: is \: given \: by \: \: \beta$
-----------------------------------------------------------------------------------------------------

----------------------------------------------------

Answer 2

Answer:

Step-by-step explanation: