Chemistry, asked by uiiwow297, 1 year ago

Explain preparation of benzene diazonium chloride.

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Answered by Anonymous07
2

Answer: The preparation of benzene diazonium chloride is given below:-

Take Aniline and react it with NaNO₂ with HCl in the presence of 273K-278K temperature then it will form benzene diazonium salt.

→This reaction is also known as Benzene Diazotiation Reaction.

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Answered by anamikapradeep7
1

hey mate...

here  is your answer...

15 ml (or 15.4 g) of aniline is dissolved in a mixture of 40 ml of concentrated hydrochloric acid and 40 ml of water. The solution is cooled to 5° C by immersing the flask in a mixture of ice and water. While stirring, the solution of 12 5 g of powdered sodium nitrite dissolved in 30 ml of water is dropwise added to the solution of aniline hydrochloride. During the diazotization heat is evolved, and the addition of sodium nitrite is interrupted, by allowing the temperature to fall again to 5° C. The temperature must not be allowed to rise above 10°, otherwise noticible decomposition of the benzenediazonium chloride to phenol will occur: on the other hand, the temperature should not be allowed to fall as low as 0° C, as at this temperature diazotization becomes very slow, and free nitrous acid may remain in the solution for a considerable time. The obtained benzene diazonium chloridesolution must be kept in ice-water until required.

>> refer to the attachment

hope it helps...

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