Question

explain reflection of light through a reactangle glass slab​

Answer 1

Answer:

Refraction through a rectangular glass slab and principle of reversibility of light:

Consider a rectangular glass slab, as shown in figure. A ray AE is incident on the face PQ at an angle of incidence i. On entering the glass slab, it bends towards normal and travels along EF at an angle of refraction r. The refracted ray EF is incident on face SR at an angle of incidence r’. The emerged ray FD bends away from the normal at an angle of refraction e.

Thus the emergent ray FD is parallel to the incident rays AE, but it has been laterally displaced with respect to the incident ray. There is shift in the path of light on emerging from a refracting medium with parallel faces.

Answer 2

Explanation:

Refraction through a rectangular glass slab and principle of reversibility of light: On entering the glass slab, it bends towards normal and travels along EF at an angle of refraction r. ... The refracted ray EF is incident on face SR at an angle of incidence r'.

After refraction at two parallel faces of a glass slab, a ray of light emerges in a direction parallel to the direction of incidence of white light. As rays of all colours emerge in the same direction, i.e., the direction of the incidence of white light, there is no dispersion.