Question

Explain rutherford scattering in motion under central forces ?

Answer 1

Rutherford scattering is the elastic scattering of charged particles by the Coulomb interaction. It is a physical phenomenon explained by Ernest Rutherford in 1911[1] that led to the development of the planetary Rutherford model of the atom and eventually the Bohr model. Rutherford scattering was first referred to as Coulomb scattering because it relies only upon the static electric (Coulomb) potential, and the minimum distance between particles is set entirely by this potential. The classical Rutherford scattering process of alpha particles against gold nuclei is an example of "elastic scattering" because neither the alpha particles nor the gold nuclei are internally excited. The Rutherford formula (see below) further neglects the recoil kinetic energy of the massive target nucleus.


the intriguing results showed that around 1 in 8000 alpha particles were deflected by very large angles (over 90°), while the rest passed through with little deflection. From this, Rutherford concluded that the majority of the mass was concentrated in a minute, positively-charged region (the nucleus) surrounded by electrons. When a (positive) alpha particle approached sufficiently close to the nucleus, it was repelled strongly enough to rebound at high angles. The small size of the nucleus explained the small number of alpha particles that were repelled in this way. Rutherford showed, using the method outlined below, that the size of the nucleus was less than about 10−14 m (how much less than this size, Rutherford could not tell from this experiment alone; see more below on this problem of lowest possible size).



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Answer 2

Rutherford scattering in motion under central forces:

• Rutherford dissipation is the flexible dispersing of charged particles by the interaction given by coulomb.
• Rutherford dissipating or scattering was first alluded to as Coulomb scattering on the grounds that it depends just upon the static electric (Coulomb) potential, and the base separation between particles is set altogether by this potential.
• The old style Rutherford dissipating procedure of alpha particles against nucleus of gold is a case of "flexible dispersing" on the grounds that neither the alpha particles nor the nuclei of gold are inside energized.
• The Rutherford equation further disregards the backlash or KE recoil for massive nuclei.  

• The fascinating outcomes indicated that around 1 of every 8000 alpha particles were diverted by huge edges (over 90°), while the rest went through with little diversion.
• From this, Rutherford reasoned that mostly all the positive charges are accumulated in center with negative electrons surrounding them.
• At the point when a (positive) alpha molecule moved toward adequately near the core, it was repulsed thereby giving evidence of small positive core.

To know more:

Explain rutherford model of atom , and if possible then please also explain cathode ray tube experiment.

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In Rutherford scattering experiment, what will be the correct angle for α scattering for an impact parameter b = 0(a) 90°

(b) 270°

(c) 0°

(d) 180°

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