Question

The average translational kinetic energy of hydrogen gas molecules at NTP will be[Boltzmann constant Kb=1.38 * 10^-23J/K]$(a)0.186 \times 10 { - }^{20} joule$$(b)0.372 \times 10 { - }^{20} joule$$(c)0.56 \times 10 { - }^{20} joule$$(d)5.6 \times 10 { - }^{20} joule$

Answer 1

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Answer 2

Given :

Boltzmann constant , $K_b=1.38\times 10^{-23}\ J/K$ .

To Find :

The average translational kinetic energy of hydrogen gas molecules at NTP.

Solution :

We know , average  translational kinetic energy is given by :

$K.E_{avg}=\dfrac{3}{2}k_bT$  ....( 1 )

We know , Temperature at NTP is given by 293 K .

Putting value of $K_b$ and T in above equation .

We get :

$K.E_{avg}=\dfrac{3}{2}\times 1.38\times 10^{-23}\times 293\\\\K.E_{avg}=6.06\times 10^{-21}\ J$

Learn More :

Thermodynamics

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