explain step by step
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madhu100:
which class question is this
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normality of hcl of 1st bottle=2/3=N1
normality of hcl of 2nd bottle=3/4=N2
normality of hcl of combined solution=68/100=Ncom
we know
Ncom (v1+v2)=N1v1+N2v2
17/25(v1+v2)=2/3(v1)+3/4(v2)
17/25-2/3(v1)=(3/4-17/25)(v2)
v1/75=7v2/100
v1/3=7/4(v2)
1st bottle solution=v1/(v1+v2) .100
=84%
2nd bottle solution=16%
normality of hcl of 2nd bottle=3/4=N2
normality of hcl of combined solution=68/100=Ncom
we know
Ncom (v1+v2)=N1v1+N2v2
17/25(v1+v2)=2/3(v1)+3/4(v2)
17/25-2/3(v1)=(3/4-17/25)(v2)
v1/75=7v2/100
v1/3=7/4(v2)
1st bottle solution=v1/(v1+v2) .100
=84%
2nd bottle solution=16%
Answered by
1
this is the answer of the same problem but another
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