Question

explain the acceleration due to gravity above the surface of the earth......answer quick

Answer 1

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WHAT IS ACCELERATION LET'S FIRST UNDERSTAND IT...


It is defined as rate of change of velocity with time.
It S.I. unit is
$change \: in \: velocity \div time \: taken \: to \: change$



NOW LET'S GO TO UR QUES...

Acceleration due to gravity is simply the acceleration produced in a body if it is left to fall freely. If an object is thrown downside by a certain height, it has some acceleration when it approaches on the earth's surface. This acceleration due to earth's gravity is called as acceleration due to gravity.

So whenever the objects falls towards earth an acceleration is involved due to earth's gravitational force.


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Answer 2

explanation-we consider earth to be a sphere of radius R and mass M..then the c.g. on the surface of the earth is g=GM/Rsq. where g is the universal gravitational constant now consider mass m at a height above the earth's surface is g(prime,say)=GM/(R+h)2..therefore g(prime)/g=R2/(R+h)2 so g(prime)= gR2/(R+h)2..so g(prime) less than g now for h much much greater than R we can show that g(prime)=g(1-2h/R)g...
if u want to know more then pls say I'll try to answer