Chemistry, asked by enbu, 11 months ago

explain the action of dilute hydrochloric acid on the following with chemical equation .(A) magnesium ribbon (b).Sodium Hydroxide . (c)

Answers

Answered by Meokhan

when dilute hydrochloric acid react with magnesium ribbon it will form magnesium chloride and hydrogen gas but when HCL react with sodium hydroxide HBL form H2O and NACL because hydrochloric acid is a acid and when acid react with base will form salt + water

Previous Question

Next Question

Similar questions

Hindi, 6 months ago

वचन बदलो - i. दीए जगमगा रहे थे। ii. चिराग जाला उतार रहा था। please answer please.....

Math, 6 months ago

1. David divides 78 by half and adds 11. What number he gets at the end ? IB (ACIO) 2017 (b) 4412 (c) 167 (d) 8312 (a) 50...

Math, 6 months ago

guestion (a) Solve: [(-19) (-5)] = [(-8)+3]...

Math, 11 months ago

train 210 metres long took 12 second to pass a 90 m long tunal find the speed of the train...

Biology, 11 months ago