Question

Explain the action of dilute hydrochloric acid on the following substances with the help of chemical equation: 1.Magnesium ribbon
2. Sodium hydroxide
3.Crushed egg shells
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[BOARD] CBSE
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No Spmming ​

Answer 1

Answer:

1. Mg + 2HCl ------------> MgCl2 + H2

2. NaOH + HCl ----------> NaCl + H2O

3.CaCO3 + 2HCl------> CaCl2 + CO2 + H2O

Answer 2

Answer:

2HCL+Mg------MgCl2+H2

when HCl react with magnesium , magnesium chloride salt is formed and hydrogen is released

HCL+NAOH------NaCl+H2O

this reaction is also called neutralization reaction, in this salt is produced Alon with water

Crushed egg cell made up of calcium carbonate so,,,,,

2HCL+CaCo3------CaCl2+H2O+Co2

in this reaction salt , water, and carbon dioxide is released

I hope it will help you......