Question

explain the auto self reduction of sulphide ores

Answer 1

Good morning frnd...


Autoreduction or air reduction is very popular reaction in metallurgy. It is a process in which sulphide ores of less electropositive metals like Hg, Pb, Cu etc., are heated in air so as to convert part of the ore into oxide or sulphate which then reacts with the remaining of sulphide ore in absence of air to give the metal and sulphur dioxide. Since no external reducing agent is used in this process that is why it is referred as auto reduction.

Examples;

Copper (Cu) ore

In the extraction of Cu, from its sulphide ore, the ore is subjected to partial roasting in air to give its oxide.

2Cu2S + 3O2 →2CuO +2SO2

When the supply of air is stopped and the temperature is raised, the rest of the sulphide reacts with oxide and forms the metal.

Cu2S +2Cu2O →6Cu +SO2

2. Mercury (Hg) ore

2HgS +3O2 → 2HgO +2 SO2

2HgO + HgS →3Hg +SO2

3. Lead (Pb) ore

2PbS +3O2 →2PbO +2SO2

2PbO +PbS →3Pb +SO2

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Answer 2

The process during which sulphide ores less electropositive metals like Mercury , Lead , Copper etc., are heated in the presence of air to convert part of the ore into oxide or sulphate which then reacts with the remaining of sulphide ore in absence of air to give the metal and sulphur dioxide