Physics, asked by Anonymous, 1 year ago

explain the experiment on Compton scattering

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Answered by fanbruhh
3
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the experiment on Compton scattering


In order to verify compton theory D Broglie and Geiger conducted an experiment in 1905.
A beam of X-rays was made to scatter in hydrogen gas and in order to detect the resulting photons and electrons two Geiger counters were arranged opposite to each other perpendicular to the beam.
One of the counter was closed with platinum foil which is sensitive to photons since the foil absorbs the electrons allowing X-rays alone to enter the chamber while the other counter was sensitive to electrons only.

When a photons enters the chamber, it interacts with the gas in the chamber producing a secondary electron. Actually the photon counter response only to a secondary electron and not to a photon striking it directly as a photon.

According to compton theory for each photon entering the photon counter, there is an electron entering the electron counter. It was observed that for every scattered photon recorded in photon counter. The explanation is that every photon entering the chamber does not produce a secondary electron. About 10% ionization was detected simultaneously in both the counters which can be explained being due to chance and coincidence. The observed coincidence can be taken due to the simultaneous emission of recoil electron and a scattered photon which supports the compton theory as a two particles effect.

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Answered by themasterofmahsea
0

the beam of x rays were made to scatter in hydrogen in order to detect the resulting photons

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