Explain the following: Oxygen does not show oxidation state of +4 and +6, while S does so.
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Sulfur has 3d orbitals available; Oxygen does not. The 3d orbitals in sulfur allow for more unpaired electrons to be established in the excited state.
4 unpaired electrons would allow +4 oxidation state.
If all of the valence electrons become unpaired, that giving a +6 oxidation state.
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