Explain the formation of Carbon dioxide with the help of electron dot
structure. (At numbers: C=6; O =8)
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Oxygen atom contains 6 valence electrons which form 2 lone pairs. Since it is bonded to only one carbon atom, it must form a double bond. Carbon atom contains four valence electrons, resulting in zero lone pairs. Therefore, it is doubly bonded to each oxygen atom.
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In carbon dioxide molecule, the two oxygen atoms are bonded on either side with carbon atom by double bonds. Thus there are 2 double bonds in CO
2 . Carbon share its two electrons In the formation of a double bond with one oxygen atom and another two electrons with another oxygen atom. In this process, both the oxygen atoms and the carbon atom acquire the stable electronic configuration of the double gas neon. The formation of CO2 molecule is shown above. Valencies of C and O are 4 and 6 respectively.
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