Explain the formation of following ionic compound by the transfer of electrons of na2O
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For the formation of Na2O: It is an ionic compound and sodium has 11 atomic number and oxygen has 8 atomic number. ... Therefore two atom of sodium will combine with one atom of oxygen and each sodium will lose one electron to oxygen and therefore completing its octet.
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Sodium electronic configuration is 1s2 2s22p63s1.so it gives one electron to form Na+ ion.Oxygen has 1s22s22p4 .so it is a non- metal and has a tendency to accept 2 electrons.
2Na+ O2- = Na2O
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