Explain the formation of h2 moleculr on the basis of valance band theory
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H2
ne( electron), np(proton)
H(a) . H(b)
ne(A) . ne(B)
np(A) . np(B)
Here
Attractive force
ne(A) -np(A)
ne(B) -np(B)
ne(A) -np(B)
ne(B) -np(A)
Repulsive force
ne(A) -ne(B)
np(B) -np(B)
Therefore no. Of attractive force is greater then no. Of repulsive
As a result H2 is formed in a molecule.
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