Question

The measure of two adjacent angles of a parallelogram are in the ratio 3:2 .find the measure of each of the angles of the parallelogram

Answer 1

Hey mate.....

here's your answer.......



let the ratio be x
Now we have 3x and 2x

we know that , In a parallelogram opposite sides are equal.
so now we have 2x, 3x, 2x, 3x

Now, 2x+3x+2x+3x=360(sum of angles of parallelogram is 360)
10x=360
x=36

Now all angles are-
2x=2*36=72
3x=3*36=108


hope it helps you..... :)

Answer 2

Answer:

Let the measures of two adjacent angles, ∠A and ∠B, of parallelogram ABCD are in the ratio of 3:2.

Let ∠A = 3x and ∠B = 2x

We know that the sum of the measures of adjacent angles is 180º for a parallelogram.

∠A + ∠B = 180º

3x + 2x = 180º

5x = 180º

• ∠A = ∠C = 3x = 108º (Opposite angles)

• ∠B = ∠D = 2x = 72º (Opposite angles)

• Thus, the measures of the angles of the parallelogram are 108º, 72º, 108º, and 72º.

.........i hope it helps you...........