Question

Explain the hybridization, type of complex formed, and the spin-type of,
(a) [Fe(CN)6]2-
(b) [Fe(H2O)6]Cl2
(c) [Ti(H2O)6]Br3 with magnetic moment corresponds to one electron

Answer 1

Answer:

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Explanation:

zero, 24

[Fe(CN)6]2-Fe2-3d6

Lowspin complex-0 unpaired e-

u=n(n+2)

0(0+2)

=0

[Fe(H2O)6]2+4 unpaired e-4(4+2)

=24