Question

explain the identity (x+a)(x-b)

Answer 1

hey there
= ( x-a) (x-b)
=x(x-b) -a(x-b)
= x^2 -xb -ax +ab
= x^2 -x(a+b ) + ab
so, (x-a) (x- b) = x^2 - x(a+b) +ab
i hope this may help you
+

Answer 2

Answer:

$(x+a)(x-b)\\=x^{2}+(a-b)x-ab$

Step-by-step explanation:

$We \: know \: the \: algebraic \: identity :\\</p><p>(x+m)(x+n)\\=x^{2}+(m+n)x+mn$

$Here, given$

$(x+a)(x-b)\\=(x+a)[x+(-b)]\\=x^{2}+(a-b)x+a\times(-b)\\=x^{2}+(a-b)x-ab$

Therefore,

$(x+a)(x-b)\\=x^{2}+(a-b)x-ab$

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