can two numbers have 24 as their hcf and 7290 as their lcm ? give reasons
Answers
Answered by
33
no its not possible
since those 2 numbers have 24 as thier common factor so that means both no.s have 8 as one of thier factors
now 7290 is a multiple of these numbers
but 7290=
![{3}^{6} \times 2 \times 5 {3}^{6} \times 2 \times 5](https://tex.z-dn.net/?f=+%7B3%7D%5E%7B6%7D++%5Ctimes+2+%5Ctimes+5)
it is not having 8 as its factor.
hence the above case is not possible
since those 2 numbers have 24 as thier common factor so that means both no.s have 8 as one of thier factors
now 7290 is a multiple of these numbers
but 7290=
it is not having 8 as its factor.
hence the above case is not possible
Answered by
1
Answer:
no its not possible it is a very wrong question but it was interesting
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