Question

Triangle ABC is circumscribing a circle of side 7 and 11 cm find third side​

Answer 1

Answer:

Given, AR=4 cm

and, AR=AQ=4 (Tangents from the same point are equal)

CQ=AC−AQ=11−4=7 cm

CQ=CP=7 cm (Tangents from the same point are equal)

BR=BP=3 cm (Tangents from the same point are equal)

Now, BC=CP+BP

BC=7+3=10 cm

Step-by-step explanation:

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