Physics, asked by saurabh5724, 10 months ago

Explain the parameters that's need to be considered to use a transistor as amplifier and state their typical value​

Answers

Answered by radharanikarmakar0
4

Explanation:

Class A Amplifier:

  • Common emitter amplifiers are the most commonly used type of amplifier as they can have a very large voltage gain

  • Common Emitter (CE) amplifiers are designed to produce a large output voltage swing from a relatively small input signal voltage of only a few millivolts’ small-signalled mainly as “small signal amplifiers” as we saw in the previous tutorials.

  • However, sometimes an amplifier is required to drive large resistive loads such as a loudspeaker or to drive a motor in a robot and for these types of applications where high switching currents are needed Power Amplifiers are required.

  • The main function of power amplifier, large-signals known as a “large signal amplifier” is to deliver power, which is the product of voltage and current to the load. Basically a power amplifier is also a voltage amplifier the difference being that the load resistance connected to the output is r, relatively low, for example a loudspeaker of 4Ω or 8Ω resulting in high currents flowing through the collector of the transistor.

  • Because of these high load currents the output transistor(s) used for power amplifier output stages such as the 2N3055 need to have higher voltage and power ratings than the general ones used for small signal amplifiers such as the BC107.

  • Since we are interested in delivering maximum AC power to the load, while consuming the minimum DC power possible from the supply we are mostly concerned with the “conversion efficiency” of the amplifier.

  • However, one of the main disadvantage of power amplifiers and especially the Class A amplifier is that their overall conversion efficiency is very low as large currents mean that a considerable amount of power is lost in the form of heat. Percentage efficiency in amplifiers is defined as the r.m.s. output power dissipated in the load divided by the total DC power taken from the supply source as shown below.

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