Question

Explain the process of breakdown of glucose in a cell (ii) in the absence of oxygen.​

Answer 1

The Anaerobic resperation takes place in cell which starts production of lactic acid in cell

The chemical equation is C6H12O6 + 6O2 → 6CO2 + 6H2O (glucose + oxygen -> carbon dioxide + water).

C6H12O6 -> 2C3H6O3 (Glucose -> Lactic acid)

equation change to this where access lactic acid is produced and less atp is obtained

Answer 2

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The process of breakdown of glucose in a cell are as follows :

1st step :

The first step in the breakdown of glucose both in presence of 02 and in absence of O2 is same. In this step, glucose is broken down into pyruvate.

2nd step :

Second step which involves further breakdown of private into simple compounds can take place in two different ways -

(a) In presence of O2 : In the presence of 02, private is converted into C02 and water. Energy released during aerobic respiration is much greater than that released during an anaerobic respiration.

(b) In absence of O2 : In the absence of 02 in yeast, pyruvate is converted into ethanol and C02 and the process is called fermentation. In absence of 02, in our muscle cells, pyruvate is converted into lactic acid. The build up of lactic acid in muscle cells causes cramps.