Explain the value of k for which the system of equations x + 3y =2 and 2x+ ky = 8 has no solution.
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for no solution, we have
a1/a2=b1/b2≠c1/c2
here, a1=1, a2=2, b1=3, b2=k, c1=2, c2=8
now
1/2=3/k≠2/8
k=2×3
k=6
a1/a2=b1/b2≠c1/c2
here, a1=1, a2=2, b1=3, b2=k, c1=2, c2=8
now
1/2=3/k≠2/8
k=2×3
k=6
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