Physics, asked by zumaira, 3 months ago

explain the velocity of projection in SHM​

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Answered by Anonymous
0

Answer:

At the time shown in the figure, the projection has position x and moves to the left with velocity v. The velocity of the point P around the circle equals ¯vmax v ¯ max . The projection of ¯vmax v ¯ max on the x-axis is the velocity v of the simple harmonic motion along the x-axis.

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Answered by kunjika158
0

At the time shown in the figure, the projection has position x and moves to the left with velocity v. The velocity of the point P around the circle equals ¯vmax v ¯ max . The projection of ¯vmax v ¯ max on the x-axis is the velocity v of the simple harmonic motion along the x-axis.

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