explain third eqution of motion
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v2 = u2 + 2aS
where,
v = final velocity,
S = displacement,
u = initial velocity,
a = acceleration (must be constant),
This equation DOES NOT relate to final velocity.
Analytical Proof
We know that,
a = dvdt
v = dSdt
Taking their ratio, we get,
av = dvdS
Hence,
a = vdvdS
Cross multiplying ‘dS’ and integrating both sides,
S∫0 a . dS = v∫u v . dv ⇒ aS = v2 - u22
v2 = u2 + 2aS
hope this helps
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