explain why 9 ^ n cannot end with the digit 0
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if 9^n ends with 0 then it must have 5 as a factor
but 9^n ={3×3)^n ={3×3} shows that 3 and 3 are the only prime factors of 5^n
also, we know from the fundamental theorem of arithmetic that the prime factorisation of each number is unique
so, 5 is not factors of 9^n
hence,9^n can be never ends with digits zero
hope it will help you
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but 9^n ={3×3)^n ={3×3} shows that 3 and 3 are the only prime factors of 5^n
also, we know from the fundamental theorem of arithmetic that the prime factorisation of each number is unique
so, 5 is not factors of 9^n
hence,9^n can be never ends with digits zero
hope it will help you
mark as brainlist
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