Art, asked by cutepgl, 4 months ago

explain why hollow cylinder of same mass and same materiap is strong than the solid cylinder of same mass and same material ??

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Answers

Answered by araj1260851
1

Answer:

Acceleration of the body (pure) rolling on the inclined plane, a=

Acceleration of the body (pure) rolling on the inclined plane, a= 1+

Acceleration of the body (pure) rolling on the inclined plane, a= 1+ mR

Acceleration of the body (pure) rolling on the inclined plane, a= 1+ mR 2

Acceleration of the body (pure) rolling on the inclined plane, a= 1+ mR 2

Acceleration of the body (pure) rolling on the inclined plane, a= 1+ mR 2 I

Acceleration of the body (pure) rolling on the inclined plane, a= 1+ mR 2 I

Acceleration of the body (pure) rolling on the inclined plane, a= 1+ mR 2 I

Acceleration of the body (pure) rolling on the inclined plane, a= 1+ mR 2 I gsinθ

Acceleration of the body (pure) rolling on the inclined plane, a= 1+ mR 2 I gsinθ

Acceleration of the body (pure) rolling on the inclined plane, a= 1+ mR 2 I gsinθ

Acceleration of the body (pure) rolling on the inclined plane, a= 1+ mR 2 I gsinθ Now as I

Acceleration of the body (pure) rolling on the inclined plane, a= 1+ mR 2 I gsinθ Now as I solidcylinder

Acceleration of the body (pure) rolling on the inclined plane, a= 1+ mR 2 I gsinθ Now as I solidcylinder

Acceleration of the body (pure) rolling on the inclined plane, a= 1+ mR 2 I gsinθ Now as I solidcylinder <I

Acceleration of the body (pure) rolling on the inclined plane, a= 1+ mR 2 I gsinθ Now as I solidcylinder <I hollowcylinder

Acceleration of the body (pure) rolling on the inclined plane, a= 1+ mR 2 I gsinθ Now as I solidcylinder <I hollowcylinder

Acceleration of the body (pure) rolling on the inclined plane, a= 1+ mR 2 I gsinθ Now as I solidcylinder <I hollowcylinder for same mass and radius

Acceleration of the body (pure) rolling on the inclined plane, a= 1+ mR 2 I gsinθ Now as I solidcylinder <I hollowcylinder for same mass and radiusa

Acceleration of the body (pure) rolling on the inclined plane, a= 1+ mR 2 I gsinθ Now as I solidcylinder <I hollowcylinder for same mass and radiusa solidcylinder

Acceleration of the body (pure) rolling on the inclined plane, a= 1+ mR 2 I gsinθ Now as I solidcylinder <I hollowcylinder for same mass and radiusa solidcylinder

Acceleration of the body (pure) rolling on the inclined plane, a= 1+ mR 2 I gsinθ Now as I solidcylinder <I hollowcylinder for same mass and radiusa solidcylinder >a

Acceleration of the body (pure) rolling on the inclined plane, a= 1+ mR 2 I gsinθ Now as I solidcylinder <I hollowcylinder for same mass and radiusa solidcylinder >a hollowcylinder

Acceleration of the body (pure) rolling on the inclined plane, a= 1+ mR 2 I gsinθ Now as I solidcylinder <I hollowcylinder for same mass and radiusa solidcylinder >a hollowcylinder

Acceleration of the body (pure) rolling on the inclined plane, a= 1+ mR 2 I gsinθ Now as I solidcylinder <I hollowcylinder for same mass and radiusa solidcylinder >a hollowcylinder

Acceleration of the body (pure) rolling on the inclined plane, a= 1+ mR 2 I gsinθ Now as I solidcylinder <I hollowcylinder for same mass and radiusa solidcylinder >a hollowcylinder Thus solid cylinder will reach the bottom first.

Acceleration of the body (pure) rolling on the inclined plane, a= 1+ mR 2 I gsinθ Now as I solidcylinder <I hollowcylinder for same mass and radiusa solidcylinder >a hollowcylinder Thus solid cylinder will reach the bottom first.

Answered by Anonymous
6

Answer:

Hollow cylinder has space inside it but solid cylinder doesn't has space inside it.

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