Explain why is the potential difference across the terminals of a cell more in an open circuit and reduced in a closed circuit?
Answers
When the electric cell is in a closed circuit the current flows through the circuit. ... So, the p.d. across the terminals in a closed circuit is less than the p.d. across the terminals in an open circuit by an amount equal to the potential drop across the internal resistance of the cell
no ideal battery or cell has no internal resistance, i.e., r=0.
So there is no voltage drop across the materials in side the battery, When it is connected in a circuit with some external elements.
When a battery is not connected in a circuit or it is open, then there is no current passing through it. So the emf the potential difference observed by measurement.
When a battery has an internal resistance r, and it is connected through a circuit, there is a current I flowing in the circuit. Hence, there is a voltage drop across this internal resistance.
So P.d. across battery=emf−r.I
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