explain why the diagonal AC of a rectangle ABCD divides it into two equal halves
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in triangle abc and adc
ab=cd
ad=bc
<adc = <abc
so bu sas axiom triangle abc and adc are equal and this proves that the diagonal ac divides the rectangle into 2 equal halves
ab=cd
ad=bc
<adc = <abc
so bu sas axiom triangle abc and adc are equal and this proves that the diagonal ac divides the rectangle into 2 equal halves
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