Explain with example of water (i) labint Heat of fusion (ii) labint heat of vapourisation
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Amount of heat required to convert unit mass of ice at 0°C into water is called specific latent heat of fusion of ice (Lf).
Lf=80 cal /g
Lf = 0.336 ×10 power 6
=3.36 ×10 power 5 J/kg
Lf=80 cal /g
Lf = 0.336 ×10 power 6
=3.36 ×10 power 5 J/kg
uvaliya2005:
Thanks for your help
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