Question

Explain with the help of a flow chart what happens if a heterozygous round seeded pea plant is crossed by homozygous wrinkled seeded pea plant? What would be the ratio of the progenies obtained from such cross??​

Answer 1

Answer:

Given:

Heterozygous round seeds are crossed with homozygous wrinkled seeds.

To find:

Ratio of progenies obtained from cross

Concept:

Round character is a dominant trait, while wrinkled character is a recessive trait.

Genotypes for parents :

1. Heterozygous round = (Rr)
2. Homozygous wrinkled = (rr)

After performing cross , we need to check the number of phenotypes and genotypes produced.

Cross:

Please refer to the attached photo to understand better.

Conclusion:

We observed the following :

• 2 genotypes are produced : (Rr) and (rr) in the F1 generation.
• 2 phenotypes are produced: Round and wrinkled.

50% of progenies having (Rr) genotype will have round phenotype.

50% progenies having (rr) genotype will have wrinkled phenotype.

Final answer :

$\boxed{Rr : rr = 2 : 2 }$

Answer 2

Explanation:

A cross is made between F1 individual and homozygous recessive individual is called Test cross.

A yellow round seeded plant (YyRr) is corssed with greed wrinkled seeded plant(yyrr). In the next generation, progeny with four types of phenotypes and genotypes are formed in 1:1:1:1 ratio. It is called Test cross.

So, the correct option is ‘YyRr and yyrr’.