Question

Explainhownitratesinthesoilpassto animalsandbacktotheatmosphereas freenitrogen
Ans:​

Answer 1

Answer:

This occurs in two steps: first, bacteria convert ammonia in to (nitrites) NO2-, and then other bacteria species convert it to NO3- (nitrate). ... The nitrogen is passed through the food chain by animals that consume the plants, and then released into the soil by decomposer bacteria when they die

Answer 2

Explanation:

ok I will change it tomorrow Ash so please thank me as much as possible and mark me as brilliant

༒ Answer ➽ 3m

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༒ Given :-

Internal Diameter of pipe = 2cm

So,

Radius of pipe will be

\sf r = 1cm = \dfrac{1}{100} mr=1cm=1001m

Flow of the water from pipe = 6 m/s.

Radius of base of cylindrical tank = 60 cm

i.e.

\sf R = \dfrac{60}{100} mR=10060m

Time = 30 min.

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༒ To Calculate :-

Height of Water in tank after 30 min.

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༒ Solution :-

We have,

\sf r = \dfrac{1}{100} mr=1001m

Flow of the water = 6 m/s

So,

Volume of water flows from pipe in 1 sec

\sf = \pi \times ( \dfrac{1}{100} {)}^{2} \times6 \: \: {m}^3=π×(1001)2×6m3

Hence,

Volume of water flows from pipe in 30 min

\begin{gathered} \sf = \pi \times ( \frac{1}{100} {)}^{2} \times6 \times (30 \times 60) \: \: {m}^{3} \\ \\ = \sf\pi \times ( \frac{1}{100} {)}^{2} \times10800 \: \: {m}^{3} \end{gathered}=π×(1001)2×6×(30×60)m3=π×(1001)2×10800m3

Let,

height of water in Tank after 30 min = h

According to the Given Condition,

After 30 min

Volume of cylindrical tank = Volume of water flows from pipe

i.e.

\begin{gathered} \sf\pi {R}^{2} h = \pi \times ( \frac{1}{100} {)}^{2} \times10800\: \: {m}^{3} \\ \\ \sf \cancel{\pi} \times ( \frac{60}{100} {)}^{2} \times h = \cancel{ \pi }\times ( \frac{1}{100} {)}^{2} \times10800 \\ \\ \sf h \times \frac{3600}{ \cancel{10000}} = \frac{10800}{ \cancel{10000} } \\ \\ \implies \Large \purple{ \bf \underline{\boxed{ \bf h = 3m}}}\end{gathered}πR2h=π×(1001)2×10800m3π×(10060)2×h=π×(1001)2×10800h×100003600=1000010800⟹h=3m

Hence,

Rise in Water level after 30 min = 3m

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