Question

Explanation:

$<p style="color:cyan;font-family:cursive;background:black;font size:25px;"> SOLVE IT$

$\bf {x}^{2} + 5x - 10 = 0$
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Answer 1

$\huge\underline\bold\red{\mathfrak{Answer}}$

For this equation: a=1, b=5, c=-10

1x²+5x-10=0

Use the Quadratic Formula with a=1, b=5, c=-10.

$x = \frac{ - b + \sqrt{ {b}^{2} - 4ac} }{2a}$

$x= \frac{ - (5) + \sqrt{(5)^{2} } - 4(1)( - 10)}{2(1)}$

$x = \frac{ - 5 + \sqrt{65} }{2} \: or \: \frac{ - 5 - \sqrt{65} }{2}$

Hope it helps :)

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Answer 2

Answer:

$\boxed{\sf\ x \leadsto \frac{ - 5 + \sqrt{ 65} }{2} \: and \: \frac{ - 5 - \sqrt{ 65} }{2} }$

Step-by-step explanation:

QUESTION➡x²-5x-10=0,

x=?

____,____,___,___,___

$\huge\mathbb{SOLUTION \mapsto} \\ \\ \sf\ using \: quadratic \: formula = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ \bf\ here \sf\pink{ \: \: a = 1 \: \green{ \: \: b =5 } \: \: \blue{c = -10}} \\ \\ \sf\ x \implies \frac{ - 5 \pm \sqrt{ {5}^{2} - 4 \times 1 \times -10} }{2 \times 1} \\ \\ \sf\ x \implies \frac{ - 5 \pm \sqrt{ 65} }{2} \\ \\ \boxed{\sf\ x \leadsto \frac{ - 5 + \sqrt{ </p><p> 65} }{2} \: and \: \frac{ - 5 - \sqrt{ 65} }{2} }$