explane it in Description
Attachments:
Answers
Answered by
2
Hello
Given equation
5x²-4xy+y²-2x+1=0
5x²can be written as 4x²+x²
(4x²-4xy+y²)+(x²-2x+1)=0
it's in the form of (a-b)²= a²-2ab+b²
( 2x-y)²+(x-1)²=0
2x-y=0
x-1=0
x=1
substitute X=1 in 2x-y=0
2(1)-y=0
y=2
value of X=1;
Value of Y=2
Given equation
5x²-4xy+y²-2x+1=0
5x²can be written as 4x²+x²
(4x²-4xy+y²)+(x²-2x+1)=0
it's in the form of (a-b)²= a²-2ab+b²
( 2x-y)²+(x-1)²=0
2x-y=0
x-1=0
x=1
substitute X=1 in 2x-y=0
2(1)-y=0
y=2
value of X=1;
Value of Y=2
Similar questions