Exponents
Solve this-
Attachments:
Answers
Answered by
2
Hey vieola!
★5^9 × 5^-9
→ 5^9+(-9)
a^m × aⁿ = a^m+n
→ 5^9-9
→ 5^0
→ 1
a^0 = 1
According to the question, 5^9×5^-9÷5^-1
→ 1/5^-1
→ 5¹ = 5
1/a^-n =aⁿ
★(-4/3)²÷(-4/3)^5
→ (-4/3)^2-5
→ (-4/3)^-3
→ (-3/4)³
→ -27/64
Hope it helps
★5^9 × 5^-9
→ 5^9+(-9)
a^m × aⁿ = a^m+n
→ 5^9-9
→ 5^0
→ 1
a^0 = 1
According to the question, 5^9×5^-9÷5^-1
→ 1/5^-1
→ 5¹ = 5
1/a^-n =aⁿ
★(-4/3)²÷(-4/3)^5
→ (-4/3)^2-5
→ (-4/3)^-3
→ (-3/4)³
→ -27/64
Hope it helps
Answered by
0
5^9 × 5^-9 ÷ 5^-1
= 5^(9+(-9)) ÷ 5^-1
[ a^m × a^n= a^(m+n)]
= 5^0 ÷ 5^-1
[a^m ÷ a^n = a^(m-n)]
= 5^(0-(-1))
= 5^(0+1)
= 5^1
= 5
___________________________________
(-4/3)^2 ÷ (-4/3)^5
= (-4/3)^2 ÷ (-4/3)^5
= (-4/3)^(2-5)
[a^m÷a^n = a^(m-n)]
= (-4/3)^-3
= (-3/4)^3
[(a/b)^-m = (b/a)^m]
= -27/64
___________________________________
= 5^(9+(-9)) ÷ 5^-1
[ a^m × a^n= a^(m+n)]
= 5^0 ÷ 5^-1
[a^m ÷ a^n = a^(m-n)]
= 5^(0-(-1))
= 5^(0+1)
= 5^1
= 5
___________________________________
(-4/3)^2 ÷ (-4/3)^5
= (-4/3)^2 ÷ (-4/3)^5
= (-4/3)^(2-5)
[a^m÷a^n = a^(m-n)]
= (-4/3)^-3
= (-3/4)^3
[(a/b)^-m = (b/a)^m]
= -27/64
___________________________________
Similar questions