express 0.47(bar on 7)in the p/q
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Let 'x' be 0.47(bar on 7).
Since the number of repeating decimal is 1,we should multiply x and it's value with 10.
10*x=10*0.47(bar on 7).
10x=4.77(bar on 7).
Now, we should subtract x and it's value from 10x and it's value.
10x-x=4.77(bar on 7)-0.47(bar on 7).
9x=4.3(bar gets cancelled).
x=4.3/9.
This still needs to be multiplied with 10 in order to make p also an integer.
43/90 is the p/q form of 0.47(bar on 7) where p and q are integers and q is mot equal to 0.
Since the number of repeating decimal is 1,we should multiply x and it's value with 10.
10*x=10*0.47(bar on 7).
10x=4.77(bar on 7).
Now, we should subtract x and it's value from 10x and it's value.
10x-x=4.77(bar on 7)-0.47(bar on 7).
9x=4.3(bar gets cancelled).
x=4.3/9.
This still needs to be multiplied with 10 in order to make p also an integer.
43/90 is the p/q form of 0.47(bar on 7) where p and q are integers and q is mot equal to 0.
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Answer:
The answer is 43/90.
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