Express 0.5 (5 bar)+ 0.45(45 bar) in p by q form, where p and q are integers
And q≠0
Please I beg you I have a test
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0.5(5 bar)
= 0 +
= 0 +
=
0.45
= 0 +
= 0 +
=
=
0.5(5 bar) + 0.45(45 bar)
- if number has bar then in fraction numerator has no. and denominator according to the no. having bar on it
- if z.xy (y bar) then no. is zx.y in decimal and in fraction zxy/9
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