Express 0.6 , 0.7 bar and 0.47 bar in the form of p by q where p and q are integers is not equal to zero and hence find the value of 0.6 + 0.7 bar+ 0.47 BAR
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Let x=0.6
Multiple by 10
10x=6
X=6/10
Let x=0.7bar
10x=7.7
10x-x=7.7-0.7
9x=7
X=7/9
Let x=0.47bar
Multiple by 10
10x=4.7
Multiple by
100x=47.7
100x-10x=47.7-4.7
90x=43
Add both side
6/10+7/9+43/90
L.C.M=90
54+70+43/90
167/90
This is a answer
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