Question

express 0.6 + 0.7bar + 0.47 in the p/q form where p and q are integers and q notequal to 0.

Answer 1

If your question is 0.6 + 0.7(bar on 7) + 0.47(bar on 47),this is the answer.

First let's solve:-
0.7 (bar on 7)

Let x = 0.7(bar on 7)

x = 0.7777..... -------(1)

10×x = 10×0.7777...10x = 7.7777.... ------(2)

(2) - (1)

10x = 7.7777...
– x = 0.7777...
-------------------
9x = 7

x = 7/9

0.7(bar on 7) = 7/9

Now, solve 0.47 (bar on 47)

Let y = 0.47 (bar on 47)

y = 0.4747... ------(1)

100 × y = 100 × 0.4747...

100y = 47.4747.. -----(2)

(2) - (1)

100y = 47.4747...
–– y = 0.4747...
-------------------------
99y = 47

y = 47/99

0.47 (bar on 47) = 47/99

=======================
0.6 + 0.7(bar on 7) + 0.47(bar on 47)

→ 6/10 + 7/9 + 47/99
→ LCM is 990
→ 6/10×99/99 + 7/9×110/110 + 47/99×10/10
→ 594/990 + 770/990 + 470/990
→ (594+770+470)/990
→ 1834/990
→ 917/495
________________
If your question is 0.6+0.7(bar on 7)+0.47

Let x = 0.7(bar on 7)
x = 0.7777..... -------(1)

10×x = 10×0.7777...10x = 7.7777.... ------(2)

(2) - (1)

10x = 7.7777...
– x = 0.7777...
-------------------
9x = 7
x = 7/9
0.7(bar on 7) = 7/9

» 6/10 + 7/9 + 47/100
» 6/10 × 90/90 + 7/9 × 100/100 + 47/100 × 9/9
» 540/900 + 700/900 + 423/900
» (540+700+423)/900
» 1663/900
__________

hope it helps

Answer 2

Answer:

190/99

Step-by-step explanation:

Let x=0.666.......  (1)

Multiply equation (1 by 10

10x = 6.666.......  (2)

Subtract equation (1) from (2)

x=6/9

Similarly 0.7bar =7/9 and 0.47bar = 47/99.

6/9+7/9+47/99=190/99