Question

Express 0.6.... in the former p/q , where possible and quality are integers and q (IS NOT EQUAL TO) 0 ..can anyone please show me the process ​

Answer 1

$let \: x = 0.6.. \\ = > x = 0.666.. \: eqn.1 \\ = > 10x = 6.666... \: eqn.2 \\ now \\ eqn.2 - eqn.1 \: we \: get \\ 10x - x = 6.666... - 0.666.... \\ = > 9x = 6 \\ = > x = \frac{6}{9} \\ = > x = \frac{2}{3} \\ therefore \\ 0.6... = \frac{2}{3} \: where \: p \: and \: q \: are \: integers \: and \: q \: not \: = \: to \: 0.$