Express 1/1+√2-√3
with rational denominator
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Step-by-step explanation:
1/(1+√2-√3)
=(1+√2+√3)/[(1+√2-√3)(1+√2+√3)]
=(+1√2+√3)/[(1+√2)^2-(√3)^2]
=(1+√2+√3)/[1+2+2√2-3]
=(1+√2+√3)/(2√2)
=[√2(1+√2+√3)]/(2√2×√3)]/(2√2×√2)
=(√2+2+√6)/4
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